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a cricket ball of 70g moving with a velocity of 0.5 m/s is stopped by a player in 0.5s what is the force applied to stop the ball

User Gene Bo
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1 Answer

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force = change in momentum / impact time
= mass (change in velocity) / impact time
= 0.07 (0.5-0) / 0.5
= 0.07N
User Futuremint
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