Question

Solve the problem by making up an equation. A man could arrive on time for an appointment if he drove the car at 40 mph; however, since he left the house 15 minutes late, he drove the car at 50 mph and arrive 3 minutes early for the appointment. How far from his house was his appointment?

Answer 1

Simple

Explanation:

Do the 163836 carry the 2 to get 328749.

Answer 2

Answer: 60 miles

Explanation:

Let x denote the distance between his home and the place of appointment and t be the time taken by him at 40 mph.

Also,
`Distance= Speed* time`

`\\\Rightarrow\ x=40t.........................(1)`

Since he left the house 15 minutes late, he drove the car at 50 mph and arrive 3 minutes early for the appointment.

15 minutes=
`(15)/(60)\ hour=0.25\ hour`

3 minutes=
`(3)/(60)\ hour=0.05\ hour`

Then actual time taken by him =t-0.25-0.05=t-0.30

`\\\Rightarrow\ x=50(t-0.30)\\\Rightarrow\ x=50t-15.........................(2)`

From (1) and (2), we have

`40t=50t-15\\\Rightarrow\ 10t=15\\\Rightarrow\ t=(3)/(2)\ hour`

Put the value of t in (1), we get

`x=40*(3)/(2)=60\ miles.........................(1)`

Hence, the distance between his home and the place of appointment = 60 miles.