Question

A sinusoidal function whose frequency is 1/6pi

Answer 1

The answer is B

Explanation:

just took the test

Answer 2

B.
`f(x)=9\sin ((x)/(3))+3`

Explanation:

We are given that,

The frequency of the function is
`(1)/(6\pi)`

The maximum and minimum value is 12 and -6.

Also, the y-intercept is 3.

From the options, we have,

Options C and D have minimum value 6. So, they does not represent the given function.

We know, 'If a function has a period P, then the function
`a+f(bx+c)` will have the period
`(P)/(|b|)`.

Also, 'The frequency is the reciprocal of the period'.

So, function
`a+f(bx+c)` will have the frequency
`(|b|)/(P)`.

From the options, we see,

Option B have the frequency,
`((1)/(3))/(2\pi)` i.e.
`(1)/(6\pi)`.

Option A have the frequency,
`(6\pi)/(2\pi)` i.e. 3

Thus, option A is not correct.

Hence, option B is the required sinusoidal function.