Question

This circle is centered at the origin, and the length of its radius is 6. what is the circle's equation?

A. X^2+y^2=36
B X^2+y^2=6
C X+y=36
D X^6+y^6=1

Answer 1

`\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~\stackrel{\textit{origin}}{(\stackrel{0}{ h},\stackrel{0}{ k})}\qquad \qquad radius=\stackrel{6}{ r} \\\\\\ (x-0)^2+(y-0)^2=6^2\implies x^2+y^2=36`

Answer 2

x^2 + y^2 = 36

Explanation:

The equation for a circle in center , radius form is

(x-h) ^2 +(y-k) ^2 = r^2

If the center is (0,0) then h=0 and k=0

The radius is 6

(x) ^2 +(y) ^2 = 6^2

x^2 + y^2 = 36