Question

Suppose that the function f is defined. , for all real numbers, as follows.

_
\ 1/4x² -4 if x≠ -2
f(x)=<
/_-1 if x=-2

find f(-5), f(-2), and f(4)

Answer 1

Answer: The values of......

`f(-5)=(9)/(4)\\ \\ f(-2)= -1\\ \\ f(4)=0`

Explanation:

Given function is:
`\left \{ {{f(x)= (1)/(4)x^2 -4, if x\\eq -2} \atop {=-1, if x=-2}} \right.`

For
`f(-5),` the value of
`x` is -5, which is not equal to -2.

So,
`f(-5)= (1)/(4)(-5)^2 -4 = (1)/(4)(25)-4 =(25)/(4)-4=(25-16)/(4)=(9)/(4)`

For
`f(-2),` the value of
`x` is -2.

So,
`f(-2)= -1`

For
`f(4),` the value of
`x` is 4, which is not equal to -2.

So,
`f(4)=(1)/(4)(4)^2 -4 =(1)/(4)(16)-4 =4-4=0`