Question

#7. M is the midpoint of PQ, the diameter of the circle O is 13in. and RM = 4in.

Find PM

Find PQ

Answer 1

• PM =6 in
• PQ = 12 in

Explanation:

MS = RS - RM

MS = 13 in - 4 in = 9 in

By the rules of crossing chords, ...

MS × MR = PM × QM

(9 in)(4 in) = PM² . . . . . QM = PM

PM = √(36 in²) = 6 in

PQ = PM + QM = 2×PM = 12 in