Question

A roller coaster car is traveling down a track at 22 m/s. The car has a mass of 2000 kg. What is the Kinetic energy of the car?

A) 22,000 J
B) 968,000 J
C) 484,000 J
D) 44,000 J

Answer 1

I found out the correct answer! All you have to do is plug in the numbers 2000 into m and 22 into v. In the equation: x = 1/2 * m * v^2 Where x equals kinetic energy. So the answer is C)

Answer 2

The kinetic energy of the car is 484000 J

Step-by-step explanation:

Given

Velocity = 22 m/s

Mass = 2000 kg

To Find:

Kinetic energy of the car= ?

Solution:

Kinetic energy of the car is given by
`KE =(1)/(2) *(mv^2)`

Where

m= mass of the car

v= velocity

KE = kinetic energy

So, substituting the values

`KE =(1)/(2) *(mv^2)`

tex]KE = \frac{1}{2}\times(2000*22^2)[/tex]

`KE = (1)/(2)*(2000*484)`

`KE = (1)/(2)*(968000)`

`KE = (968000)/(2)`

KE = 484000 J