Question

A 0.40 kg soccer ball is kicked so that its incoming velocity of 5 m/s is changed to an outgoing velocity of -25 m/s. What impulse does the player apply to the ball?

Answer 1

`{\triangle}p=p_(f)-p_(i)=-10-2=-12kgms^(-1)`

Explanation:

It is given that the mass of the soccer ball is=0.40 kg and it is kicked with the velocity of=
`5ms^(-1)`, then the initial momentum will be:

`p_(i)=mv=0.40{*}5=2kgms^(-1)`

Then, the velocity is changed to
`-25ms^(-1)`, then the final momentum will be:

`p_(f)=mv=0.40{*}(-25)=-10kgms^(-1)`

Now, Impulse that the player applied to the ball will be:

`{\triangle}p=p_(f)-p_(i)=-10-2=-12kgms^(-1)`