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Polygon ABCD is a rectangle what is the area

User Kamelkev
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Solution:

As, You have Written Polygon ABCD is a rectangle.

It is a Four sided Polygon , having all it's interior angles equal to 90°.As well as Opposite sides are equal(AB=CD,AD=BC), equal diagonals(AC=B D).

Join any of the diagonal of Rectangle either AC or B D.

In Right Δ ABC , Right angled at B


{\text{Area (Right triangle ABC)}} =(1)/(2)* AB * BC---(1)

In Right Δ ADC , Right angled at D


{\text{Area (Right triangle ABC)}} =(1)/(2)* AD * DC---(2)

Adding (1) and (2) that is LHS to LHS and RHS to RHS

Ar( Δ ABC) +Ar( Δ ADC)
=(1)/(2)*[ AB * BC+ AD * DC]\\\\=(1)/(2)[2 * AB * BC][\text{As, AB=CD, and BC=AD}]\\\\ = AB * BC

So, Area of Rectangle= Product of any two Adjacent Sides

Polygon ABCD is a rectangle what is the area-example-1
User Madav
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