Answer:
Square
Explanation:
Given are 3 options with same dimension of 12 feet. The condition is base area should be minimum for maximum volume
A) A hemisphere has
![V=(2)/(3) \pi ((12)/(2) )^3\\=452.57\\Base area = \pi ((12)/(2) )^2\\=113.04\\Ratio=4.00](https://img.qammunity.org/2020/formulas/mathematics/high-school/sw5z7d8u3nzcgum1m8g8vx3mdvxffl4n3w.png)
B) A cube with side length 12 ft
![V=6^3 =216\\Base area = 36\\Ratio = 6](https://img.qammunity.org/2020/formulas/mathematics/high-school/dewzihptb3275812m4we819b8uournhkdv.png)
C) A cone with diameter 12 ft and height 10 ft
![V=(1)/(3) \pi(6^2)10\\=377.14\\Base area =113.04\\Ratio =3.34\\](https://img.qammunity.org/2020/formulas/mathematics/high-school/uapy4b6whvlagsce1qla6bfu73sgcq7afw.png)
D) A square pyramid
![V=(lwh)/(3) \\=(144(9))/(3) \\=432\\Base area = 144\\Ratio =3](https://img.qammunity.org/2020/formulas/mathematics/high-school/nzns9sk80ixmd3pq53xkq7hf2wsdn5oaqj.png)
To maxmize the ratio of floor area to volume, we have to maximise the ratio of volume to floor area
Hence of these 4 figures square is the best one that meets the criteria