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A force of 9.00 newtons acts at an angle of 19.0 to the horizontal. What is its component in the horizontal direction?

User Jon List
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1 Answer

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Solution

In this question we have given,

Force, F=9N

angle,α=19degree with horizontal

therefore,

Component of force in horizontal direction is given as


F_(x) =F* Cos\alpha


F_(x) =9* Cos19


F_(x) =9* .946


F_(x) =8.51N

User Turbulencetoo
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