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The length of a rectangle is 5 times the width. If the perimeter is to be greater than 36 meters. What are the possible values for the width?

User IPO
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Answer:

The width must be greater than 3 meters.

Explanation:

Let w represent the width. Then 5w will represent the length, which is 5 times the width. The perimeter is the total of the side lengths of the rectangle, so is ...

P = 2w + 2(5w) = 12w

We want this to be greater than 36 m, so ...

P > 36 m

12w > 36 m . . . . . . . substitute our expression for P

w > 3 m . . . . . . . . . . divide by 12

The possible values for width are those values that are more than 3 meters.

User Posdef
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