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What is the distance between (3,k+1) and (2k,k-1)

What is the distance between (3,k+1) and (2k,k-1)
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What is the distance between (3,k+1) and (2k,k-1)

User Riley Lark
by
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1 Answer

5 votes

Answer:

We have the formula:


\sqrt{(2k-3)^(2)+(k-1-k-1)^(2)  } = \sqrt{4k^(2)-12k+9+4 } = \sqrt{4k^(2)-12k+13} ;

Explanation:


User Jurgen Strydom
by
8.4k points
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