What is the distance between (3,k+1) and (2k,k-1)

asked Apr 28, 2020 201k views

3 votes

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5 votes

Answer:

We have the formula:

$\sqrt{(2k-3)^(2)+(k-1-k-1)^(2)  } = \sqrt{4k^(2)-12k+9+4 } = \sqrt{4k^(2)-12k+13} ;$

Explanation:

Jurgen Strydom answered May 4, 2020

6.2k points

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