Question

Find the sixth term of the following geometric sequence.

Answer 1

`a_(6)` = -
`(7)/(16)`

Explanation:

The n th term of a geometric sequence is

`a_(n)` = a
`r^(n-1)`

where a is the first term and r the common ratio

here a = 14 and r =
`(-7)/(14)` = -
`(1)/(2)`, hence

`a_(6)` = 14 ×
`(-1/2)^(5)` = 14 × -
`(1)/(32)` = -
`(7)/(16)`