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For what values of a is the sum of the fractions 2a−1 / 4 and a−1 /3 positive?

User Serge Mask
by
7.9k points

1 Answer

2 votes

Answer:


a>(7)/(10)

Explanation:

We are given fractions as


(2a-1)/(4)


(a-1)/(3)

now, we can add both fractions


(2a-1)/(4)+(a-1)/(3)

we can see that both denominators are different

so, we can find common denominator


(3* (2a-1))/(3* 4)+(4*(a-1))/(4* 3)


(3* (2a-1)+4*(a-1))/(3* 4)

now, we can combine them


(6a-3+4a-4)/(3* 4)


(10a-7)/(12)

To make it positive, both numerator and denominator must be positive

Since, bottom is 12 ...which is positive

so, numerator should also be positive

so, we get


10a-7>0

now, we can solve for a

we get


a>(7)/(10)


User Egon Olieux
by
8.7k points

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