Question

A solution contains 225 g of sodium chloride, NaCl, dissolved in enough water to make a 0.25 L of solution. What is the molarity of the solution?

Answer 1

We know that molarity is the number of moles of solute dissolved per litre of solution

`Molarity=(molesofsolute)/(volume-of-solution)`

Moles = mass / molar mass

molar mass of NaCl = atomic mass of Na + atomic mass of Cl = 23+ 35.5 = 58.5

`moles=(225)/(58.5)=3.85`

therefore

`molarity=(3.85)/(0.25)=15.4M`

Thus molarity of given solution will be 15.4 M