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In cents, what is the least total amount that cannot be obtained by using a combination of fewer than eight coins from a collection of pennies, nickels, dimes and quarters?

1 Answer

2 votes

Answer:

94 cents

Explanation:

Using eight coins, the maximum is
2 dollars, so we need to find a value lower than that. If we imagine
8 pennies, and add one to that, since we can make any value under
8 cents, we will get
9 cents. We can make this with a nickel, so we also need to be out of range of nickels, so we should try
40+1. We can make this with dimes, so we should try
8\cdot10+1.
81 can be made with quarters, so we should try
200+1 and get
201 cents. But, we cannot forget about subtracting from these values. If we try
40-1, we get
39, which is made with dimes. Trying
8\cdot10-1 makes
79, but if we keep moving it down to the nearest multiple of
25, or a quarter, we will get
74.
74 can be made with
8 coins though, but if we take it away again down to
7\cdot10-1, we get
69. This looks hopeful. This has
2 quarters,
1 dime,
1 nickel, and four pennies. If we keep trying and move it down to
64, we can still make it. If we keep moving down till we get to the LCM of the values, we get
50-1=49. Making this does works, so now we know it is between
75 cents and
200 cents. Trying the nearest multiple of
5 minus
1, we get
79. This obviously works, so we need to get away from the multiple of
25. Trying
84, we get
3,
1, and
4 coin types, so this works. Now try
89. This is
3 quarters,
1 dime, and four pennies. Trying
94, we get
3 quarters,
1 dime,
1 nickel, and four pennies.There is nothing lower than this, so we have found it! :D This took me very long to do, and even I learned something from doing your super hard question! Thanks for the workout!



EDIT: Oops! I did less than or equal to! But you can use the same logic to do it again!

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