Question

What acceleration is produced when a 3,000-N force acts on a 1,200-kg car?Ignore the friction

Answer 1

Answer:
`2.5(m)/(s^(2))`

According to Newton's 2nd Law of Motion (in the specific case when the mass
`m` is constant) the acceleration
`a` that a body acquires is directly proportional to the exerted force
`F` on the body.

As shown in the following equation:

`F=ma` (1)

We already know the value of the mass of the car and the force excerted on it. So, we need to find the value of the acceleration from equation (1):

`a=(F)/(m)` (2)

And substitute the known values:

`a=(3000N)/(1200kg)`

At this point, note that
`1N=1kg(m)/(s^(2))`

Taking this into account, the acceleration of the car is:

`a=2.5(m)/(s^(2))`