Answer:
width of the rectangle=x=4in and length of the rectangle=11in
Explanation:
Let the width of the rectangle be x, then according to the question, length is one less than three times its width that is l=3x-1.
Now, width=b=x and length=l=3x-1, thus
Perimeter of the rectangle= 2(l+b)
⇒
![30=2(3x-1+x)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/e7oolca958z6igzfdzacaf9tk3nv4r5i0a.png)
⇒
![15=(3x-1+x)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/mfdh9hwigjh1u342j01r3skxrgtl2dd330.png)
⇒
![15=4x-1](https://img.qammunity.org/2020/formulas/mathematics/middle-school/c477431uolkx05dj42emjdudbsc1abqm1z.png)
⇒
![16=4x](https://img.qammunity.org/2020/formulas/mathematics/middle-school/46x2v20y4gm3e48dzupaqpl4hejflanz29.png)
⇒
![x=4in](https://img.qammunity.org/2020/formulas/mathematics/middle-school/4jzwkiurw7f2l1k6oj3ft3d7i5wb3azcnm.png)
Thus, width of the rectangle=x=4in and length of the rectangle=l=3x-1=3(4)-1=12-1=11in.