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Edward cleaned a windowpane with a width of 5 feet and a length of 3 feet in 1/4 of an hour. What is the speed, in square feet per hour, at which Edward cleaned the pane?

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Answer:


60\ (ft^2)/(h).

Explanation:

If a windowpane is of the width of 5 feet and the length of 3 feet, then the area of this windowpane is


A_(windowpane)=\text{length}\cdot \text{width}=3\cdot 5=15\ ft^2.

If Edward cleaned a windowpane in 1/4 of an hour, then he cleaned 15 square feet in 1/4 of an hour. Thus, the speed at which Edward cleaned the pane is


(15)/((1)/(4))=15\cdot 4=60\ (ft^2)/(h).

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