Question

if ABC is a isosceles triangle with sides(2a+b)cm, (6a+2b+1)cm and a base of 4a cm, if it's perimeter is 28 find sides​

Answer 1

a=1.5, b= 3

Explanation:

sum of all sides will give us perimeter. Therefore

2a+b+6a+2b+1+4a=28

12a+3b+1=28

12a+3b=27....eqn1

since t two sides of this isosceles triangle are equal:

2a+b=4a

2a=b

`a=(b)/(2)`

substituting
`(b)/(2)`
`.` in the first equation whenever we encounter a we will have:

`12((b)/(2))+3b=27\\`

6b+3b=27

9b=27

b=3

therefore
`a= (b)/(2) =(3)/(2) =1(1)/(2) or 1.5`