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3 votes
What is the argument of 3 - 3i?

300°

315°

330°

345°

User Mufazmi
by
4.8k points

1 Answer

3 votes

Answer:

315

Explanation:

z = a+bi

The modulus is the sqrt ( a^2 +b^2)

and the argument (I call it theta) is equal to arctan (b/a)

We have z = 3-3i

We are looking for the argument of z

theta = arctan (-3/3)

= -45 degrees

They don't like negative arguments so add 360 degrees to it. It is the same value, we just loop once around the circle.

-45+360 =

315


User Tienou
by
4.5k points
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