Answer:

Explanation:
The equation of the ellipse is

where
are the coordinates of the center.
If the vertices of an ellipse are at A(1, 5) and B(1, -5), then the center is the midpoint of the segment AB. Hence, the center has coordinates

The coordinates of the vertices satisfy the equation:

If (3, 0) is a point on the ellipse, then its coordinates satisfy the equation:

Therefore, the equation of the ellipse is
