Question

What is the value of 13x^-3y^-1 when x=-1 and y=4

Answer 1

-49/4

Explanation:

(13)(-1^-3)-(-3)(4^-1)

Negative exponents move the x and y to the denominator.

(13/-1)-(-3/4)= -12 1/4 = -49/4

Answer 2

`-(13)/(4)`

Explanation:

Given expression,

`13x^(-3)y^(-1)`

By using
`a^m=(1)/(a^(-m))`

`=(13)/(x^3y)`

We have, x = -1 and y = 4

By substituting the values,

`=(13)/((-1)^3(4))`

`=(13)/(-4)`

`=-(13)/(4)`

Hence, the value of given expression is
`-(13)/(4)`.