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2 votes
Which is the equation in slope-intercept form for the line that passes through (3, 7) and is perpendicular to 3x-5y=8

A. y=5/3x+2

B. y=3/5x+2

C. y=-5/3x+12

D. y=-3/5x+5

User Gudbergur
by
5.2k points

2 Answers

2 votes

Answer:

I got c

Explanation:

User Beef
by
4.8k points
5 votes

Answer:

C

Explanation:

Perpendicular lines have slopes which are the negative reciprocal of each other. To find the slope, convert 3x-5y=8 into y=mx+b form.

3x-5y=8

-5y = -3x +8

y = 3/5 x - 8/5

The slope is 3/5 so its perpendicular slope is -5/3. Write the equation of this line through the point (3,7) using point slope form. Then simplify into y=mx+b form.


y-y_1=m(x-x_1)\\y-7 = -(5)/(3)(x-3)\\y-7=-(5)/(3)x + 5\\y = -(5)/(3)x+12

User Davisjp
by
5.5k points
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