Question

Using the equation

C12H22O11+12O2-->12CO2+11H2O

if 156 L of O2 at STP are consumed how many moles of sucrose are required?

Answer 1

0.5804 moles sucrose are required to react with 156 liters of oxygen.

Step-by-step explanation:

Since the conditions of the gas are STP, standard temperature and pressure, we can use a very useful conversion factor that is valid for all gases at STP: All gases occupy 22.4 liters per mole of gas:

22.4 L/mole

156 liters of O2 at STP may be converted to moles O2 by dividing by the conversion factor:

(156 L)/(22.4 L/mole) = 6.96 moles O2

The balanced equation tells us that 12 moles of O2 are consumed for every 1 mole of sucrose. That's a molar ratio of (1 mole sucrose/12 moles O2).

We can use this ratio to determine the moles of sucrose required to react with 6.96 moles of O2:

(6.96 moles O2)*((1 mole sucrose/12 moles O2) = 0.5804 moles sucrose