Question

What is the inverse of the given relation

y=7x^2-3

a. y= +/- sqrt x+3/7
b. x= sqrt y+3/7
c. y^2 = x+3/7
d. y= +/- sqrt x-3/7

Answer 1

y= +/- sqrt x+3/7

Answer 2

A

Explanation:

To find the inverse, we will follow the steps below:

1. Interchange x and y

2. solve for new y

Hence,

`y=7x^2 - 3\\x=7y^2-3\\x+3=7y^2\\(x+3)/(7)=y^2\\+-\sqrt{(x+3)/(7)} =y`

Answer is
`y=+-\sqrt{(x+3)/(7)}`

Answer choice A is right.