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Factor the polynomial: -2x^3 - 4x^2 - 6x

A. 2x(x^2 + 2x + 3)

B. -2x(x^2 + 2x +3)

C. -2x(-x^2 - 4x - 6)

D. -2x(-x^2 - 2x - 3)

User Spassas
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1 Answer

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Answer:Go To TigerAlgebra.com for questions like yours



-2x3-4x2-6x

Final result :

-2x • (x2 + 2x + 3)

Step by step solution :

Step 1 :

Equation at the end of step 1 :

((0 - (2 • (x3))) - 22x2) - 6x

Step 2 :

Equation at the end of step 2 :

((0 - 2x3) - 22x2) - 6x

Step 3 :

Step 4 :

Pulling out like terms :

4.1 Pull out like factors :


-2x3 - 4x2 - 6x = -2x • (x2 + 2x + 3)


Trying to factor by splitting the middle term

4.2 Factoring x2 + 2x + 3


The first term is, x2 its coefficient is 1 .

The middle term is, +2x its coefficient is 2 .

The last term, "the constant", is +3


Step-1 : Multiply the coefficient of the first term by the constant 1 • 3 = 3


Step-2 : Find two factors of 3 whose sum equals the coefficient of the middle term, which is 2 .


-3 + -1 = -4

-1 + -3 = -4

1 + 3 = 4

3 + 1 = 4


Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored


Final result :

-2x • (x2 + 2x + 3)

Explanation:


User Aaron Thoma
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