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(3v^5+8v^3_10v^2)_(-12v^5+4v^3+14v^2)

User Wassup
by
4.2k points

1 Answer

6 votes

Answer:

(3v5+8v3+10v2)+(-12v5+4v3+14v2)

Final result :

-3v2 • (3v3 - 4v - 8)

Step by step solution :

Step 1 :

Equation at the end of step 1 :

(((3•(v5))+(8•(v3)))+(10•(v2)))+(((0-(12•(v5)))+(4•(v3)))+(2•7v2))

Step 2 :

Equation at the end of step 2 :

(((3•(v5))+(8•(v3)))+(10•(v2)))+(((0-(12•(v5)))+22v3)+(2•7v2))

Step 3 :

Equation at the end of step 3 :

(((3•(v5))+(8•(v3)))+(10•(v2)))+(((0-(22•3v5))+22v3)+(2•7v2))

Step 4 :

Equation at the end of step 4 :

(((3•(v5))+(8•(v3)))+(2•5v2))+(-12v5+4v3+14v2)

Step 5 :

Equation at the end of step 5 :

(((3•(v5))+23v3)+(2•5v2))+(-12v5+4v3+14v2)

Step 6 :

Equation at the end of step 6 :

((3v5 + 23v3) + (2•5v2)) + (-12v5 + 4v3 + 14v2)

Step 7 :

Step 8 :

Pulling out like terms :

8.1 Pull out like factors :


-9v5 + 12v3 + 24v2 = -3v2 • (3v3 - 4v - 8)


Polynomial Roots Calculator :

8.2 Find roots (zeroes) of : F(v) = 3v3 - 4v - 8

Polynomial Roots Calculator is a set of methods aimed at finding values of v for which F(v)=0


Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers v which can be expressed as the quotient of two integers


The Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading Coefficient


In this case, the Leading Coefficient is 3 and the Trailing Constant is -8.


The factor(s) are:


of the Leading Coefficient : 1,3

of the Trailing Constant : 1 ,2 ,4 ,8


Let us test ....


P Q P/Q F(P/Q) Divisor

-1 1 -1.00 -7.00

-1 3 -0.33 -6.78

-2 1 -2.00 -24.00

-2 3 -0.67 -6.22

-4 1 -4.00 -184.00

-4 3 -1.33 -9.78

-8 1 -8.00 -1512.00

-8 3 -2.67 -54.22

1 1 1.00 -9.00

1 3 0.33 -9.22

2 1 2.00 8.00

2 3 0.67 -9.78

4 1 4.00 168.00

4 3 1.33 -6.22

8 1 8.00 1496.00

8 3 2.67 38.22


Polynomial Roots Calculator found no rational roots


Final result :

-3v2 • (3v3 - 4v - 8)


Explanation:


User Paul Oskar Mayer
by
4.7k points