Question

The sum of the roots of x^2+6x-55=0

Answer 1

The sum is -6

Answer 2

The sum of the roots is
`-6`

Explanation:

we know that

The formula to solve a quadratic equation of the form
`ax^(2) +bx+c=0` is equal to

`x=\frac{-b(+/-)\sqrt{b^(2)-4ac}} {2a}`

in this problem we have

`x^(2) +6x-55=0`

so

`a=1\\b=6\\c=-55`

substitute in the formula

`x=\frac{-6(+/-)\sqrt{6^(2)-4(1)(-55)}} {2(1)}`

`x=\frac{-6(+/-)√(256)} {2}`

`x=\frac{-6(+/-)16} {2}`

`x1=\frac{-6(+)16} {2}=5`

`x2=\frac{-6(-)16} {2}=-11`

The roots are
`5,-11`

Find the sum of the roots

`5+(-11)=-6`