Answer:
Let x represents the number of lilies and y represents the number of tulips in the bouquet.
As per the statement:
A bouquet of lilies and tulips has 12 flowers.
⇒x+y = 12 .....[1]
It is also given that lilies cost $3 each and tulips cost $2 each the bouquet cost $32.
⇒
.....[2]
Multiply equation [1] by 3 we get;
3x+ 3y = 36 .....[3]
Subtract equation [2] from [3] we get;
![3x+3y-(3x+2y)=36-32](https://img.qammunity.org/2020/formulas/mathematics/middle-school/uwndrd61h2wprypxap5ahtf34om9njsqrr.png)
![3x+3y-3x-2y=36-32](https://img.qammunity.org/2020/formulas/mathematics/middle-school/bjub5wb8dlkp5dp2wqy2ckwfxk3tyerd32.png)
Combine like terms;
![y=4](https://img.qammunity.org/2020/formulas/mathematics/high-school/jszmtghs7756m7cy884501rsvdvozrx7z2.png)
Substitute the value of y in [1] we get;
x + 4 = 12
Subtract 4 from both sides we get;
x = 8
Therefore, the number of lilies are 8 and the number of tulips are 4