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n parallelogram LMNO, MP = 21 m, LP = (y + 3) m, NP = (3y – 1) m, and OP = (2x – 1) m. What are the values of x and y? x = 10, y = 1 x = 10, y = 2 x = 11, y = 1

2 Answers

6 votes

Answer:

D. x=11 m, y=2 m

Explanation:

Just took the Unit Test on Edg (2020-2021)!!

User Ajo
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5 votes

Answer:

The value of x = 11 and y = 2

Explanation:

Given : parallelogram LMNO, MP = 21 m, LP = (y + 3) m, NP = (3y – 1) m, and OP = (2x – 1) m.

We have to find values of x and y.

Let P be the point of intersection of diagonals OM and LN.

In a parallelogram diagonal bisects at right angles and point of intersection divide diagonal in equal parts.

Thus, OP = MP and LP = PN

OP = MP , substitute the values, we get,

(2x-1) = 21

⇒ 2x = 22

x = 11

LP = PN , substitute the values, we get,

y + 3 = 3y -1

⇒ 3y - y = 4

⇒ 2y = 4

y = 2

Thus, the value of x = 11 and y = 2


n parallelogram LMNO, MP = 21 m, LP = (y + 3) m, NP = (3y – 1) m, and OP = (2x – 1) m-example-1
User SaeX
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