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Suppose DK is an angle bisector of △DEF.


Given: EK=2, FK=5, DF=10. Find DE.

Suppose DK is an angle bisector of △DEF. Given: EK=2, FK=5, DF=10. Find DE.-example-1

1 Answer

5 votes

Answer:


DE=4

Explanation:

We have been provided a graph of a triangle and we are asked to find the length of segment DE.

Angle bisector theorem states that if a ray bisects an angle of a triangle, then it bisects the opposite side of triangle into segments that are proportional to other two sides.

By angle bisector theorem we can set proportions of the given sides as:


(DE)/(EK)=(DF)/(FK)

Upon substituting our given values in above proportion we will get,


(DE)/(2)=(10)/(5)

Upon multiplying both sides of our equation by 2 we will get,


(DE)/(2)* 2=2* (10)/(5)


DE=2* 2


DE=4

Therefore, the length of segment DE is 4 units.

User Tcarvin
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