Question

How much energy must a refrigerator absorb from 225 g of water so that the temperature of the water will drop from 35°c to 5°c

Answer 1

Heat energy required to change the temperature is given by

`Q = ms\Delta T`

here we know that

`m = 225 g = 0.225 kg`

`s = 4186 J/kg C`

`T_i = 5 ^0C`

`T_f = 35 ^0C`

now from above formula we will have

`Q = (0.225 kg)(4186 J/kg C) (35 - 5)`

`Q = 28255.5 J`

So it will remove 28255.5 J heat from the water