Question

Which point corresponds to the real zero of the graph of y = log3 (x+2) - 1?

O (-1,-1)
O (1,0)
O (-1,0)
O (0,-.369)
E

Answer 1

(1, 0 )

Explanation:

using the rule of logarithms

`log_(b)` x = n ⇒ x =
`b^(n)` , then

y =
`log_(3)` (x + 2) - 1

to find the zero let y = 0 , that is

`log_(3)` (x + 2) - 1 = 0 ( add 1 to both sides )

`log_(3)` (x + 2) = 1 , then

x + 2 =
`3^(1)` = 3 ( subtract 2 from both sides )

x = 1

the zero is (1, 0 )