Question

Please help i’m stuck!!
FIND GE AND FJ
HE = 6
FE= 8

Answer 1

GE=10

FJ=5

Explanation:

We know that in a traingle

`a^(2)+b^(2)  =c^(2)`

a=HE=6

b=FE=8

Once we enter it into the equation, we find that we get

36+64=100

The square root of 100=10

GE=HF so HE=10.

Half of HE(10) is FJ(5)

Hope this help :)