Answer:
C 18x^2y^2 ( 3xy^2) ^ 1/3
Explanation:
3x * (648 x^4y^8) ^ (1/3)
We know that we can separate these into separate roots
3x * (648 )^ 1/3 (x^4) ^1/3 ( y^8) ^ (1/3)
The a power to a power means the powers are multiplied a^b^c = a^(b*c)
3x * (648 )^ 1/3 (x^4/3) ( y^8/3)
Breaking these into pieces
3x (8 )^ 1/3 (27)^ 1/3 (3)^1/3 (x^3/3) x ^ 1/3 * y ^ 6/3 y ^2/3
3x *2 *3 * 3^1/3 * x * x^1/3 * y^2 * y^2/3
Taking the pieces outside the root and inside the root
3x *2 *3 * * x * * y^2 * 3^1/3 * x^1/3 * y^2/3
18x^2y^2 ( 3xy^2) ^ 1/3