Question

In a heat engine of 1000 j of heat enters the system and the piston does 500 j of work what is the final internal energy of the system if the inital energy was 2000 j

we have to do all of these down here
1)Write the equation
2)list out your know variables
3)plug the numbers into the equations
4)solve
5)write your solution statemtn that includes inital energuy and final energuy added

Answer 1

Answer : The final energy of the system if the initial energy was 2000 J is, 3500 J

Solution :

(1) The equation used is,

`\Delta U=q+w\\\\U_(final)-U_(initial)=q+w`

where,

`U_(final)` = final internal energy

`U_(initial)` = initial internal energy

q = heat energy

w = work done

(2) The known variables are, q, w and
`U_(initial)`

initial internal energy =
`U_(initial)` = 2000 J

heat energy = q = 1000 J

work done = w = 500 J

(3) Now plug the numbers into the equation, we get

`U_(final)-(2000J)=(1000J)+(500J)`

(4) By solving the terms, we get

`U_(final)-(2000J)=(1000J)+(500J)`

`U_(final)-(2000J)=1500J`

`U_(final)=2000J+1500J`

`U_(final)=3500J`

(5) Therefore, the final energy of the system if the initial energy was 2000 J is, 3500 J