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A roller coaster is traveling at 13 mi./s when you purchase a hill that is 400 m long and down the hill exonerate at 4.0 m/s squared what is the final velocity of the posterior found your answer to the nearest number

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I will Apply the equation:

2as = v^2 - u^2

v = √ (2a + u^2)

v = √(2 x 4 x 400 + 13 ^2)

v = 58 m/s

User Ryantdecker
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