Question

Upon decomposition, one sample of magnesium fluoride produced 1.65 kg of magnesium and 2.56 kg of fluorine. A second sample produced 1.32 kg of magnesium. Part A How much fluorine (in grams) did the second sample produce?

Answer 1

Answer : The mass of fluorine in second sample produces, 2.048 grams

Law of definite proportion states that in a chemical compound, the components of the element are in fixed ratio.

The given chemical compound is magnesium fluoride. In the magnesium fluoride the components of the element magnesium and fluorine are in fixed ratio that is, 1 : 1

`(M_(Mg))/(M_(F))=(m_(Mg))/(_(F))`

`M_(Mg)` = mass of magnesium in sample 1 = 1.65 g

`M_(F)` = mass of fluorine in sample 1 = 2.56 g

`m_(Mg)` = mass of magnesium in sample 2 = 1.32 g

`m_(F)` = mass of fluorine in sample 2 = x

Now put all the give values in the above relation, we get

`(1.65g)/(2.56g)=(1.32g)/(x)`

`x=2.048g`

Therefore, the mass of fluorine in second sample produces, 2.048 grams