Question

40 points, please help with all of them

Answer 1

`\large\boxed{Q1.\ \text{2 times greater}}\\\\\boxed{Q2.\ J. 3}\\\\\boxed{Q3.\ B. -(4)/(5)}`

Explanation:

The slope-intercept form of an equation of a line:

`y=mx+b`

m - slope

b - y-intercept

The formula of a slope:

`m=(y_2-y_1)/(x_2-x_1)`

Q1.

We have the equation of a line p in the standard form

`4x-3y=7`

Convert to the slope-intercept form:

`4x-3y=7` subtract 3x from both sides

`-3y=-4x+7` divide both sides by (-3)

`y=(4)/(3)x-(7)/(3)`

The slope
`m_1=(4)/(3)`

From the table we have the points (4, 3) and (7, 5). Calculate the slope of line q:

`m_2=(5-3)/(7-4)=(2)/(3)`

Divide the slope of p by the slope of q:

`(4)/(3):(2)/(3)=(4)/(3)\cdot(3)/(2)=2`

Q2.

Parallel line have the same slope. Therefore, if we have the equation of the line in the slope-intercept form, then we have the slope:

`y=3x+2\to m=3`

Q3.

Parallel line have the same slope.

Calculate the slope from given points (-11, 5) and (-6, 1):

`y=(1-5)/(-6-(-11))=(-4)/(-6+11)=(-4)/(5)=-(4)/(5)`