ANSWER
There are 16 fiction books
Step-by-step explanation
Let the number of nonfiction books be
![n](https://img.qammunity.org/2020/formulas/mathematics/high-school/yvu6uf7kr7phwj693qzkkr5zuzyb8qqemh.png)
Then the number of fiction books is
![f=(2n)/(5)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/tpfzm705xxv6ceutt5hh0moj2uuz80epp8.png)
If there are 56 books in the library, then
![n + f= 56](https://img.qammunity.org/2020/formulas/mathematics/middle-school/5461djx75l3jg987qtkpfkdm1sola5plcc.png)
This implies that,
![n + (2n)/(5) = 56](https://img.qammunity.org/2020/formulas/mathematics/middle-school/stauihui8i1qwubuqvx9u46qraz4nj6ym1.png)
Multiply through by 5 to get,
![5n + 2n = 280](https://img.qammunity.org/2020/formulas/mathematics/middle-school/y4o9v07fqsf3zssp2fwogvmbfv9ugp8wsk.png)
![7n= 280](https://img.qammunity.org/2020/formulas/mathematics/middle-school/pg74dpsr4y8ecp6c0h8af5jbygutpnktat.png)
Divide through by 7 to get,
![n = (280)/(7)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/we09cn6t8yl03ez9z3gg857fk2udloflkg.png)
![n= 40](https://img.qammunity.org/2020/formulas/mathematics/middle-school/f9gbizt0dn3chbia4k8t4znqy1m8frmnkc.png)
Therefore the number of fiction books
![f=(2*40)/(5)=16](https://img.qammunity.org/2020/formulas/mathematics/middle-school/7b43nky2u4iqr3szbjniqnxguswvycdlj3.png)
Or
![f=56 - 40 = 16](https://img.qammunity.org/2020/formulas/mathematics/middle-school/hp1pcilx46uk3pacph850gx1u8kxmegm0p.png)