Answer:
Explanation:
Alright, lets get started.
Please refer the diagram I have attached.
The point (8, -15) shows it is in 4th quadrant.
side X is 8 and side Y is -15.
We can find side R with help of Pythagorean theorem.
![R^2=8^2+(-15)^(2)=289](https://img.qammunity.org/2020/formulas/mathematics/high-school/rjkpkz88pjpo1h2azdmzk99vj1yt8q99g4.png)
Taking square root,
![R = 17](https://img.qammunity.org/2020/formulas/mathematics/high-school/xitbeock1y2kus36z2j8vm3692dh4yf4kd.png)
sinΘ=
![(Y)/(R)=(-15)/(17)](https://img.qammunity.org/2020/formulas/mathematics/high-school/v0kqvj14rhrbnz8kig42uqya6hls3w8nb4.png)
cosΘ=
![(X)/(R)=(8)/(17)](https://img.qammunity.org/2020/formulas/mathematics/high-school/3gge5smxepv8um82bpjc4py1asv9melazd.png)
tanΘ=
![(X)/(Y)=(-15)/(8)](https://img.qammunity.org/2020/formulas/mathematics/high-school/qxb1fbqw2jdv90qpdi3lg3x6dbhkve1l1u.png)
cscΘ=
![(R)/(X)=(17)/(-15)=-(17)/(15)](https://img.qammunity.org/2020/formulas/mathematics/high-school/w2bquqg37uyh5l7lporahz9phqa5kq4qse.png)
secΘ=
![(R)/(X)=(17)/(8)](https://img.qammunity.org/2020/formulas/mathematics/high-school/rt26laotn93haxbr9v4h6b9bocvue39ukx.png)
cotΘ=
![(X)/(Y)=(8)/(-15)=-(8)/(15)](https://img.qammunity.org/2020/formulas/mathematics/high-school/s2w67ud7t1pon4js5txi9it2pky0xfu2we.png)
Answer
Hope it will help :)