Question

Multiply Conjugates Using the Product of Conjugates Pattern

In the following exercises, multiply each pair of conjugates using the Product of Conjugates Pattern
329. (9c + 5)(9c − 5)

Answer 1

The product is the difference of squares is
`$$\left(9c+5\right)\left(9c-5\right)=81{{c}^2}-25$$`

Explanation:

Explanation

• The given expression is (9 c+5)(9 c-5).

• We have to multiply the given expression.
• Square the first term 9c. Square the last term 5 .

`$$\begin{aligned}&(9 c+5)(9 c-5)=(9 c)^(2)-(5)^(2) \\&(9 c+5)(9 c-5)=81 c^(2)-25\end{aligned}$$`