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A fireman is standing 30 m directly west of a burning building. His ladder reaches 50m up the side of the building. What is the angle of elevation to the closest degree of his ladder?

User Murtaza
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1 Answer

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Answer:

As per the statement:

You can see the diagram as shown below.

Distance of fireman stands away from the building = 30 m

Length of the ladder = 50 m

Using Cosine ratio:


\cos \theta = \frac{\text{Adjacent side}}{\text{Hypotenuse side}} ....[1]

From the diagram:

Adjacent side = 30 m

Hypotenuse side = 50 m

Substitute these values in [1] to solve for angle of elevation(
\theta)


\cos \theta = (30)/(50) = 0.6

or


\theta = \cos^(-1) (0.6)

Simplify:


\theta = 53.13^(\circ)

Therefore, the angle of elevation to the closest degree of the ladder is 51.13 degree

A fireman is standing 30 m directly west of a burning building. His ladder reaches-example-1
User Serge Pedroza
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