Question

acetylene gas c2h2 undergoes combustion to produce carbon dioxide and water vapor How many grams of water are produced by the same amount of C2H2?

Answer 1

Answer: The amount of water produced in the given reaction is
`0.692x` grams.

Step-by-step explanation:

Let us assume that the initial amount of acetylene gas given be 'x' grams. Now, to calculate the number of moles, we will use the formula:

`\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}` ....(1)

Given mass of acetylene = x grams

Molar mass of acetylene = 26 g/mol

Putting values in above equation, we get:

`\text{Number of moles of acetylene}=(xg)/(26g/mol)=(x)/(26)mol`

The reaction of combustion of acetylene is given by the equation:

`2C_2H_2+5O_2\rightarrow 4CO_2+2H_2O`

By Stoichiometry of the reaction:

2 moles of acetylene produces 2 moles of water.

So,
`(x)/(26)` moles of acetylene will produce =
`(2)/(2)* (x)/(26)=(x)/(26)` moles of water.

Now, to calculate the amount of water produced, we use equation 1:

Molar mass of water = 18 g/mol

Moles of water =
`(x)/(26)mol`

Putting values in equation 1, we get:

`(x)/(26)mol=\frac{\text{Mass of water}}{18g/mol}`

`\text{Mass of water}=(x)/(26)* 18=0.692x` grams