Question

Please helpppp

The area of a rectangle is 5.612×10 to the 14th power centimeters square. The length of the rectangle is 9.2×10 to the 7 cm . Find the perimeter of the rectangle.

Answer 1

`P = 1.962 * 10^8`

Explanation:

The area of a rectangle is A = L*W. This means
`A = 5.612*10^(14)` and
`L = 9.2*10^7` then the area of the rectangle in the formula would be:

`5.612*10^14 = 9.2*10^7 (W)\\W = (5.612*10^14)/(9.2*10^7) \\W = 0.61 * 10 ^7 = 6.1*10^6`

To find the perimeter, add each of the sides. The length is
`9.2*10^7` and the width is
`6.1*10^6`.

`P = 9.2*10^7 + 9.2*10^7 + 6.1*10^6+6.1*10^6\\P = 18.4*10^7 + 12.2*10^6\\P = 184000000+12200000\\P = 1.962 * 10^8`