Question

On Wednesday, mr. miles walked and ran 9/10 of the trail. Then he walked 1\8 of the trail back and stopped to rest. What fraction of the course was mr. Miles from the beginning of the trail when he stopped?

Answer 1

31/40 of the trail

Explanation:

he completed 9/10 of the trail (or 72/80 because 9*8 is 72)

He went back 1/8 of the trail (or 10/80 because 1*10 is 10)

72-10 is 62

he went 62/80, simplified is 31/40 of the trail

Answer 2

Answer: 31/40 of the trail.

Explanation:

At the start, he walked 9/10 of the trail.

Then, he backed 1/8 of the trail

The, the amount that he walked is:

d = 9/10 - 1/8

now, we must find a common multipler between 8 and 10, we know that 8*5 = 40 = 10*4

d = (4/4)*(9/10) - (5/5)*(1/8) = (4*9 - 5*1)/40 = (36 - 5)/40 = 31/40

So when he stops, he is at 31/40 of the trail.