Question

If the specific heat of a metal is 0.850 J/g °C, what is its atomic weight?

Answer 1

Its atomic weight is 0.00753N

Step-by-step explanation:

Dulong and Petit law states that atoms of all elements have the same heat capacity so their specific heat is inversely related to their respective atomic weights.

i.e
`S_(H)`
`\alpha (1)/(A_(w) )`

where
`S_(H)` is the specific heat of the object and
`A_(w)` is the atomic weight of the object.

⇒
`S_(H)` ×
`A_(w)` = constant = 6.4

`S_(H)` = 0.850J/g°C = 850 J/KgK

`A_(w)` =
`(6.4)/(850)`

= 0.00753N

Answer 2

As we know that with respect to oxygen atom taken as reference the product of atomic mass and specific heat of a metal will remain constant.

this product is equal to 0.38

so here we will say that let atomic mass of the metal is M

so with respect to oxygen atom its mass is given as

`m = (M)/(16)`

now we will have

`(M)/(16) * 0.850 = 0.38`

now we will have

`M = 7`

so atomic mass of the metal is 7 g/mol