Question

The width of a rectangle is 6 inches less than the length The perimeter is 44 inches Find the length and the width.

Answer 1

Length is 14 inches. Width is 8 inches.

Explanation:

Let the length of rectangle is l.

Let the width of rectangle is w.

From question statement,we observe that

The width of a rectangle is 6 inches less than the length.

w= l-6

P = 2l+2w = 44 inches

2l + 2( l-6) = 44

2l+2l-12 = 44

4l-12 = 44

4l = 44+12

4l = 56

Dividing by 4

l = 56/4

l = 14 inches

Hence, the width is

w = 14-6 = 8 inches

Hence, the length of rectangle is 14 inches and the width is 8 inches.

Answer 2

`l=14\:in.,w=8\:in.`

Explanation:

Let the length of the rectangle be
`l\:in.` and the width be
`w\:in.`.

Then

`w=l-6...(1)`

The perimeter is given by

`P=2w+2l...(2)`

We put equation (1) into equation (2) to get;

`\Rightarrow 44=2(l-6)+2l`

We can expand the bracket here. But let us divide through by 2 first to get;

`\Rightarrow 22=(l-6)+l`

Group like terms to get;

`\Rightarrow 22=l-6+l`

`\Rightarrow 22+6=l+l`

`\Rightarrow 28=2l`

Divide by 2 again;

`\Rightarrow 14=l`

The length is 14 inches.

`w=14-6=8`

The width is 8 inches.